Below is a particle on its line, and the three graphs that describe it. Press play — or drag the time cursor. Watch the dot move, reverse, and race: velocity is the slope of position, acceleration is the slope of velocity, and the badge reads out the direction and whether it's speeding up or slowing down at every instant.
Here's the rule the whole topic hinges on: a particle speeds up when velocity and acceleration share a sign, and slows down when their signs disagree. A negative acceleration does not mean "slowing" — it only slows the particle if the particle is moving in the positive direction. The sign chart lays out every interval of our example, .
Read it in columns: on (1, 2) the particle moves left (v < 0) with negative acceleration — same sign, so it's speeding up. On (2, 3) acceleration flips positive while velocity is still negative — opposite signs, so it's slowing down toward its turn at t = 3.
Velocity is the derivative of position; acceleration is the derivative of velocity — so a = v′ = x″. Each step down measures the rate of the one above.
Velocity has a sign (direction); speed = |v| never does. A velocity of −8 and +8 are opposite directions but the same speed.
v > 0 moves in the positive direction, v < 0 the negative. Where v = 0 and changes sign, the particle is momentarily at rest and turns around.
The particle speeds up exactly when v·a > 0 (v and a agree) and slows when v·a < 0. Equivalently: speed grows when a points the same way as motion.
Because the particle backtracks, two "how far" questions have different answers. Displacement is where it ended up minus where it started — direction counts, so backtracking cancels. Total distance adds up every leg as a positive length — split the trip at each turn (v = 0) and sum the pieces.
Six problems on our particle . Try each before revealing.
Six fast checks. Pick an answer to see whether it's right and why — then work through all six.
Only if velocity is positive. If v < 0 and a < 0, the particle is speeding up (moving negative, faster). Always compare the two signs.
Speed is |v| and is never negative. "Speeding up" is about |v| growing, which is the v·a > 0 test — not about the sign of v alone.
Only when the particle never turns around. If v changes sign, split at each turn and add the absolute legs for total distance; displacement is just end − start.
At rest means v = 0, not a = 0. At a turning point v = 0 but acceleration is usually nonzero — that's what pulls it back.
Velocity is often a quadratic with two zeros. Both can be turning points; test the sign of v on each interval before concluding direction.
On the position graph, speed is the steepness, not the height. The particle can be far out (high x) yet momentarily still (slope 0).